# Trigonometric Identities

When equation involving a variable is true for all values of the variable, it is called an **identity**.

Let XOX′ and YOY′ be the rectangular axes. Let A be any point on OX. Let the ray OA start rotating in the plane in an anti-clockwise direction about the point O till it reaches the final position OA′ after some interval of time. Let ∠A′OA = θ. Take any point P on the ray OA′. Draw PM ⊥ OX.

In right angled ΔPMO,

$$ \sin \theta = \frac{PM}{OP} $$

$$ \cos θ = \frac{OM}{OP} $$

Squaring and adding,

$$ \sin^2 \theta + \cos^2 \theta = \left( \frac{PM}{OP} \right)^2 + \left( \frac{OM}{OP} \right) ^2 $$

$$ = \frac{PM^2 + OM^2}{OP^2} $$

$$ = \frac{OP^2}{OP^2} $$

$$ = 1 $$

### Identities

$$ \sin^2 \theta + \cos^2 \theta = 1 $$

$$ \sec^2 \theta - \tan^2 \theta = 1 \text{ or } \sec^2 \theta = 1 + \tan^2 \theta $$

$$ \csc^2 \theta - \cot^2 \theta = 1 \text{ or } \csc^2 \theta = 1 + \cot^2 \theta $$

### Method to Solve Questions on Trigonometric identities

**Step 1:** Choose L.H.S. or R.H.S., whichever looks to be easy to simplify.

**Step 2: **Use different identities to simplify the L.H.S. (or R.H.S.) and arrive at the result on the other hand side.

**Step 3:** If you don’t get the result on R.H.S. (or L.H.S.) arrive at an appropriate result and then simplify the other side to get the result already obtained.

**Step 4:** As both sides of the identity have been proved to be equal the identity is established.